First task is done
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48 changed files with 857 additions and 1217 deletions
30
2025.03.28/Example/Makefile
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30
2025.03.28/Example/Makefile
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CFLAGS = -mfpmath=sse -fstack-protector-all -W -Wall -Wextra -Wunused \
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-Wempty-body -Wlogical-op -Wold-style-declaration -Wmissing-parameter-type \
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-Wignored-qualifiers -Winit-self -Wshadow -Wtype-limits \
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-Wpointer-arith -Wformat-security -Wmissing-format-attribute -Wformat=1 \
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-Wdeclaration-after-statement -Wbad-function-cast -Wnested-externs \
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-Wmissing-prototypes -Wmissing-declarations -Wold-style-definition \
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-Wcast-align -Werror -pedantic -pedantic-errors -Wfloat-equal \
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-Wwrite-strings -Wno-long-long -std=gnu99 -Wstrict-prototypes \
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-Wmissing-field-initializers -Wpointer-sign -fopenmp -O3
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TARGET = a01.exe
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OBJ = main.o solve.o array_io.o init_f.o
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$(TARGET): $(OBJ)
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gcc $^ -o $@ -lm -fopenmp -lssp
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main.o: main.c
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gcc $(CFLAGS) -c $^
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solve.o: solve.c
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gcc $(CFLAGS) -c $^
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array_io.o: array_io.c
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gcc $(CFLAGS) -c $^
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init_f.o: init_f.c
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gcc $(CFLAGS) -c $^
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clean:
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del *.o *.exe
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40
2025.03.28/Example/array_io.c
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40
2025.03.28/Example/array_io.c
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#include <stdio.h>
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#include "array_io.h"
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io_status read_matrix(double *a, int m, int n, const char *name)
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{
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int i, j;
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FILE *fp;
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if (!(fp = fopen(name, "r"))) return ERROR_OPEN;
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for (i = 0; i < m; i++)
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for (j = 0; j < n; j++)
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if (fscanf(fp, "%lf", a + i * n + j) != 1)
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{fclose(fp); return ERROR_READ;}
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fclose(fp);
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return SUCCESS;
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}
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void print_matrix(const double *a, int m, int n, int p)
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{
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int mp = (m > p ? p : m);
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int np = (n > p ? p : n);
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int i, j;
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for (i = 0; i < mp; i++)
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{
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for (j = 0; j < np; j++)
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printf(" %10.3e", a[i * n + j]);
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printf("\n");
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}
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}
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void init_matrix(double *a, int m, int n, int k)
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{
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double (*q)(int, int, int, int);
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double (*f[])(int, int, int, int) = {f1, f2, f3, f4};
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int i, j;
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q = f[k-1];
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for (i = 0; i < m; i++)
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for (j = 0; j < n; j++)
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a[i * n + j] = q(m, n, i+1, j+1);
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}
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11
2025.03.28/Example/array_io.h
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2025.03.28/Example/array_io.h
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#ifndef ARRAY_IO_H
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#define ARRAY_IO_H
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#include "io_status.h"
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#include "init_f.h"
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io_status read_matrix(double *a, int m, int n, const char *name);
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void print_matrix(const double *a, int m, int n, int p);
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void init_matrix(double *a, int m, int n, int k);
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#endif
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30
2025.03.28/Example/init_f.c
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2025.03.28/Example/init_f.c
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#include "init_f.h"
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#include <stdlib.h>
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#define MAX(n, m) (n < m ? m : n)
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double f1(int m, int n, int i, int j)
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{
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return MAX(n, m) - MAX(i, j) + 1;
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}
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double f2(int m, int n, int i, int j)
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{
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(void)n;
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(void)m;
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return MAX(i, j);
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}
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double f3(int m, int n, int i, int j)
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{
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(void)n;
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(void)m;
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return abs(i - j);
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}
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double f4(int m, int n, int i, int j)
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{
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(void)n;
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(void)m;
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return 1./(i+j-1);
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}
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9
2025.03.28/Example/init_f.h
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2025.03.28/Example/init_f.h
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#ifndef INIT_F_H
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#define INIT_F_H
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double f1(int m, int n, int i, int j);
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double f2(int m, int n, int i, int j);
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double f3(int m, int n, int i, int j);
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double f4(int m, int n, int i, int j);
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#endif
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13
2025.03.28/Example/io_status.h
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2025.03.28/Example/io_status.h
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#ifndef IO_STATUS_H
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#define IO_STATUS_H
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#define LEN 1234
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typedef enum _io_status
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{
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SUCCESS,
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ERROR_OPEN,
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ERROR_READ
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} io_status;
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#endif
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112
2025.03.28/Example/main.c
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2025.03.28/Example/main.c
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#include <stdio.h>
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#include <stdlib.h>
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#include <time.h>
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#include "array_io.h"
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#include "io_status.h"
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#include "solve.h"
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/* ./a.out m n p k_a [filename_a] k_x [filename_x] */
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int main(int argc, char *argv[])
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{
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double t, *a, *x;
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int n, m, p, k_a, k_x, r1, r2, task = 1;
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char *name_a = 0, *name_x = 0;
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if (!((argc == 6 || argc == 7 || argc == 8) &&
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sscanf(argv[1], "%d", &m) == 1 &&
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sscanf(argv[2], "%d", &n) == 1 &&
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sscanf(argv[3], "%d", &p) == 1 &&
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sscanf(argv[4], "%d", &k_a) == 1 &&
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(k_a >= 0 && k_a <= 4) &&
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(!(k_a == 0 && argc == 6)) &&
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((k_a == 0 && sscanf(argv[6], "%d", &k_x) == 1) ||
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(k_a != 0 && sscanf(argv[5], "%d", &k_x) == 1)) &&
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(k_x >= 0 && k_x <= 4) &&
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(!(k_x == 0 && argc == 6)) &&
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(!((k_a == 0 && k_x == 0) && argc != 8))))
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{
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printf("Usage: %s m n p k_a [filename_a] k_x [filename_x]\n", argv[0]);
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return 1;
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}
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if (argc != 6)
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{
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int i_x = 6;
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if (k_a == 0) {name_a = argv[5];i_x++;}
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if (k_x == 0) name_x = argv[i_x];
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}
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a = (double *)malloc(n * n * sizeof(double));
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if (!a)
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{
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printf("Not enough memory\n");
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return 2;
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}
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x = (double *)malloc(n * sizeof(double));
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if (!x)
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{
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free(a);
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printf("Not enough memory\n");
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return 2;
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}
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if (name_a)
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{ /* из файла */
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io_status ret;
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ret = read_matrix(a, n, n, name_a);
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do {
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switch (ret)
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{
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case SUCCESS:
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continue;
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case ERROR_OPEN:
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printf("Cannot open %s\n", name_a);
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break;
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case ERROR_READ:
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printf("Cannot read %s\n", name_a);
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break;
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}
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free(a);
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free(x);
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return 3;
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} while (0);
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} else init_matrix(a, n, n, k_a);
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if (name_x)
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{
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io_status ret;
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ret = read_matrix(x, n, 1, name_x);
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do {
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switch (ret)
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{
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case SUCCESS:
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continue;
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case ERROR_OPEN:
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printf("Cannot open %s\n", name_x);
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break;
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case ERROR_READ:
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printf("Cannot read %s\n", name_x);
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break;
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}
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free(a);
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free(x);
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return 3;
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} while (0);
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} else init_matrix(x, n, 1, k_x);
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printf("Matrix A:\n");
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print_matrix(a, n, n, p);
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printf("Vector x:\n");
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print_matrix(x, n, 1, p);
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t = clock();
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res = t1_solve(a, x, n, m);
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t = (clock() - t) / CLOCKS_PER_SEC;
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printf("Vector x_m:\n");
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print_matrix(x, 1, n, p);
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printf("%s : Task = %d Res1 = %e Res2 = %e Elapsed = %.2f\n", argv[0], task, r1, r2, t);
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free(a);
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free(x);
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return 0;
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}
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40
2025.03.28/Example/solve.c
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2025.03.28/Example/solve.c
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#include "solve.h"
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#include <math.h>
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#define eps 1e-17
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int compare(const double a, const double b)
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{
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if (a - b > eps) return 1;
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else if (b - a > eps) return -1;
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return 0;
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}
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double t1_solve(double *a, int m, int n)
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{
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int i, j;
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double cur = 0, maximum = 0;
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for (i = 0; i < n; i++)
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{
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cur = 0;
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for (j = 0; j < m; j++)
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cur += fabs(a[i * m + j]);
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if (compare(cur, maximum) == 1) maximum = cur;
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}
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return maximum;
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}
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void matvec_mul(int n, double * restrict A, double * restrict x, double * restrict x_k)
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{
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#pragma omp parallel for
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for (int i = 0; i < n; i++)
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{
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double sum = 0;
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#pragma omp simd reduction(+:sum)
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for (int j = 0; j < n; j++)
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sum += A[i * n + j] * x[j];
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x_k[i] = sum;
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}
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}
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8
2025.03.28/Example/solve.h
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2025.03.28/Example/solve.h
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#ifndef SOLVE_H
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#define SOLVE_H
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int compare(const double a, const double b);
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double t1_solve(double *a, int m, int n);
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void matvec_mul(int n, double * restrict A, double * restrict x, double * restrict x_k);
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#endif
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