Add Matvej's solve

This commit is contained in:
AZEN-SGG 2025-05-02 01:18:28 +03:00
parent c5ae5840ff
commit 3e90cc7ebb
22 changed files with 916 additions and 105 deletions

View file

@ -20,7 +20,7 @@ else
CLEAN = rm -f
endif
TARGET = a04.$(EXE)
TARGET = a02.$(EXE)
OBJ = main.o solve.o init_f.o
%.o: %.c

View file

@ -3,59 +3,112 @@
#include <math.h>
static int cl = 0;
static int cl_f = 0;
static int cl_d = 0;
int get_call_count (void)
int get_call_function_count (void)
{
return cl;
return cl_f;
}
int get_call_derivative_count (void)
{
return cl_d;
}
double f0 (double x)
{
cl++;
cl_f++;
(void)x;
return 1;
}
double d0 (double x)
{
cl_d++;
(void)x;
return 0;
}
double f1 (double x)
{
cl++;
return (x * 1e-100) - 1.0;
cl_f++;
return ((x * 1e-100) - 1.0) * 1e100;
}
double d1 (double x)
{
cl_d++;
return x;
}
double f2 (double x)
{
cl++;
cl_f++;
return 4 - x * x;
}
double d2 (double x)
{
cl_d++;
return - 2 * x;
}
double f3 (double x)
{
double x_2 = x * x;
cl++;
cl_f++;
return x * x_2 + 3 * x_2 + 16;
}
double d3 (double x)
{
cl_d++;
return 3 * x * x + 6 * x;
}
double f4 (double x)
{
double x_2 = x * x;
cl++;
cl_f++;
return 3 - 2 * x_2 - x_2 * x_2;
}
double d4 (double x)
{
double x_2 = x * x;
cl_d++;
return -4 * x - 4 * ((x * x) * x);
}
double f5 (double x)
{
cl++;
cl_f++;
return sqrt(fabs(x) + 1) - 2;
}
double d5 (double x)
{
cl_d++;
return (((signbit(x)) ? -1 : 1) * (1.0 / (sqrt(fabs(x) + 1))) * 0.5;
}
double f6 (double x)
{
cl++;
cl_f++;
return sqrt(sqrt(fabs(x) + 1) + 1) - 2;
}
double d6 (double x)
{
double sqrt_x = sqrt(fabs(x) + 1);
cl_d++;
return (((signbit(x)) ? -1 : 1) * (1.0 / (sqrt(sqrt_x + 1) * sqrt_x))) * 0.25;
}

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@ -2,12 +2,21 @@
#define INIT_F_H
int get_call_count (void);
int get_call_derivative_count (void);
double f0 (double x);
double d0 (double x);
double f1 (double x);
double d1 (double x);
double f2 (double x);
double d2 (double x);
double f3 (double x);
double d3 (double x);
double f4 (double x);
double d4 (double x);
double f5 (double x);
double d5 (double x);
double f6 (double x);
double d6 (double x);
#endif

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@ -3,62 +3,48 @@
#include <math.h>
#include "init_f.h"
#include "status.h"
#include "solve.h"
/* ./a.out a b eps M k */
/* ./a.out x_0 eps M k */
int main(int argc, char *argv[])
{
double t, a, b, eps, x = 0;
int m, k, cl, it = 0, task = 4;
status ret;
double t, x_0, eps, x = 0;
int m, k, cl, it, task = 2;
double (*f) (double);
double (*f_lst[]) (double) = {f0, f1, f2, f3, f4, f5, f6, sin}; // TODO: Remove sin
int len_f = sizeof(f_lst) / sizeof(f_lst[0]);
double (*d) (double);
double (*d_lst[]) (double) = {d0, d1, d2, d3, d4, d5, d6, cos}; // TODO: Remove cos
if (
!((argc == 6) &&
sscanf(argv[1], "%lf", &a) == 1 &&
sscanf(argv[2], "%lf", &b) == 1 &&
(a <= b) &&
(sscanf(argv[3], "%lf", &eps) == 1 && (eps >= 0)) &&
((sscanf(argv[4], "%d", &m) == 1) && m > 0) &&
((sscanf(argv[5], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
!((argc == 5) &&
sscanf(argv[1], "%lf", &x_0) == 1 &&
(sscanf(argv[2], "%lf", &eps) == 1 && (eps >= 0)) &&
((sscanf(argv[3], "%d", &m) == 1) && (m > 0)) &&
((sscanf(argv[4], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
) {
fprintf(stderr, "Usage: %s a b eps M k\n", argv[0]);
return 1;
fprintf(stderr, "Usage: %s x_0 eps M k\n", argv[0]);
return -1;
}
f = f_lst[k];
t = clock();
ret = t4_solve(f, a, b, eps, m, &x, &it);
it = t2_solve(f, d_lst[k], x_0, eps, m, &x);
t = (clock() - t) / CLOCKS_PER_SEC;
cl = get_call_count();
// printf("x = %e\tf(x) = %e\n", x, f(x));
do {
switch (ret)
{
case SUCCESS:
continue;
case RUN_TIME:
fprintf(stderr, "Error: with code %d - Not enough iterations!\n", ret);
break;
case EQUAL:
fprintf(stderr, "Error: with code %d - The dots degenerated into one!\n", ret);
break;
}
if (it >= m)
{
fprintf(stdout, "%s : Task = %d NOT FOUND Count = %d T = %.2f\n", argv[0], task, cl, t);
return ret;
} while (0);
printf("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], task, x, f(x), it, cl, t);
return 0;
return -2;
} else
{
printf("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], task, x, f(x), it, cl, t);
return 0;
}
}

View file

@ -1,62 +1,33 @@
#include "solve.h"
#include "status.h"
#include <math.h>
#include <float.h>
status t4_solve (
int t7_solve (
double (*f) (double),
double a, double b,
double eps, int m, double *x, int *m_it
double x_0, double eps,
int m, double *x
) {
int it = 0;
status ret = SUCCESS;
double c = DBL_MAX, y, y_a = f(a), y_b = f(b);
double y = f(x_0);
if (fabs(y_a) - eps < DBL_EPSILON)
if (fabs(y - x_0) - eps < DBL_EPSILON)
{
*x = a;
return SUCCESS;
} if (fabs(y_b) - eps < DBL_EPSILON)
{
*x = b;
return SUCCESS;
} if (fabs(fabs(y_b) - fabs(y_a)) < DBL_EPSILON)
{
*x = a;
return EQUAL;
*x = x_0;
return 1;
}
for (it = 0; it < m; ++it)
{
c = b - ((b - a) / (y_b - y_a)) * y_b;
y = f(c);
x_0 = y;
y = f(x_0);
if (fabs(y) - eps < DBL_EPSILON)
{
ret = SUCCESS;
if (fabs(y - x_0) - eps < DBL_EPSILON)
break;
} else if (fabs(y_a) - fabs(y_b) > DBL_EPSILON)
{
a = c;
y_a = y;
} else if (fabs(y_b) - fabs(y_a) > DBL_EPSILON)
{
b = c;
y_b = y;
} else
{
ret = EQUAL;
break;
}
}
if (it >= m)
ret = RUN_TIME;
*x = c;
*m_it = it;
*x = x_0;
return ret;
return it;
}

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@ -1,12 +1,10 @@
#ifndef SOLVE_H
#define SOLVE_H
#include "status.h"
status t4_solve (
int t7_solve (
double (*f) (double),
double a, double b,
double eps, int m, double *x, int *m_it
double x_0, double eps,
int m, double *x
);
#endif

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@ -1,10 +0,0 @@
#ifndef STATUS_H
#define STATUS_H
typedef enum _status {
SUCCESS,
RUN_TIME,
EQUAL,
} status;
#endif