Add Matvej's solve

This commit is contained in:
AZEN-SGG 2025-05-02 01:18:28 +03:00
parent c5ae5840ff
commit 3e90cc7ebb
22 changed files with 916 additions and 105 deletions

View file

@ -3,62 +3,48 @@
#include <math.h>
#include "init_f.h"
#include "status.h"
#include "solve.h"
/* ./a.out a b eps M k */
/* ./a.out x_0 eps M k */
int main(int argc, char *argv[])
{
double t, a, b, eps, x = 0;
int m, k, cl, it = 0, task = 4;
status ret;
double t, x_0, eps, x = 0;
int m, k, cl, it, task = 2;
double (*f) (double);
double (*f_lst[]) (double) = {f0, f1, f2, f3, f4, f5, f6, sin}; // TODO: Remove sin
int len_f = sizeof(f_lst) / sizeof(f_lst[0]);
double (*d) (double);
double (*d_lst[]) (double) = {d0, d1, d2, d3, d4, d5, d6, cos}; // TODO: Remove cos
if (
!((argc == 6) &&
sscanf(argv[1], "%lf", &a) == 1 &&
sscanf(argv[2], "%lf", &b) == 1 &&
(a <= b) &&
(sscanf(argv[3], "%lf", &eps) == 1 && (eps >= 0)) &&
((sscanf(argv[4], "%d", &m) == 1) && m > 0) &&
((sscanf(argv[5], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
!((argc == 5) &&
sscanf(argv[1], "%lf", &x_0) == 1 &&
(sscanf(argv[2], "%lf", &eps) == 1 && (eps >= 0)) &&
((sscanf(argv[3], "%d", &m) == 1) && (m > 0)) &&
((sscanf(argv[4], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
) {
fprintf(stderr, "Usage: %s a b eps M k\n", argv[0]);
return 1;
fprintf(stderr, "Usage: %s x_0 eps M k\n", argv[0]);
return -1;
}
f = f_lst[k];
t = clock();
ret = t4_solve(f, a, b, eps, m, &x, &it);
it = t2_solve(f, d_lst[k], x_0, eps, m, &x);
t = (clock() - t) / CLOCKS_PER_SEC;
cl = get_call_count();
// printf("x = %e\tf(x) = %e\n", x, f(x));
do {
switch (ret)
{
case SUCCESS:
continue;
case RUN_TIME:
fprintf(stderr, "Error: with code %d - Not enough iterations!\n", ret);
break;
case EQUAL:
fprintf(stderr, "Error: with code %d - The dots degenerated into one!\n", ret);
break;
}
if (it >= m)
{
fprintf(stdout, "%s : Task = %d NOT FOUND Count = %d T = %.2f\n", argv[0], task, cl, t);
return ret;
} while (0);
printf("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], task, x, f(x), it, cl, t);
return 0;
return -2;
} else
{
printf("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], task, x, f(x), it, cl, t);
return 0;
}
}