Task 4 and 5 are done

2025.05.09/01Ex/main.c

@@ -19,7 +19,7 @@ int main (int argc, char *argv[])
 			!((argc == 4) && 
 			sscanf(argv[1], "%lf", &x) == 1 &&
 			((sscanf(argv[2], "%lf", &h) == 1) && (h > 0)) &&
-			((sscanf(argv[3], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
+			((sscanf(argv[3], "%d", &k) == 1) && ((0 <= k) && (k < len_f))))
 	) {
 		fprintf(stderr, "Usage: %s x h k\n", argv[0]);
 		return -1;

2025.05.09/02Ex/main.c

@@ -19,7 +19,7 @@ int main (int argc, char *argv[])
 			!((argc == 4) && 
 			sscanf(argv[1], "%lf", &x) == 1 &&
 			((sscanf(argv[2], "%lf", &h) == 1) && (h > 0)) &&
-			((sscanf(argv[3], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
+			((sscanf(argv[3], "%d", &k) == 1) && ((0 <= k) && (k < len_f))))
 	) {
 		fprintf(stderr, "Usage: %s x h k\n", argv[0]);
 		return -1;

2025.05.09/04Ex/Makefile

@@ -21,7 +21,7 @@ else
 endif
 
 TARGET = a04.$(EXE)
-OBJ = main.o solve.o init_f.o
+OBJ = main.o solve.o
 
 %.o: %.c
 	gcc $(WFLAGS) $(LDFLAGS) -c $< -o $@

2025.05.09/04Ex/init_f.c

@@ -1,61 +0,0 @@
-#include "init_f.h"
-
-#include <math.h>
-
-
-static int cl = 0;
-
-int get_call_count (void) 
-{
-	return cl;
-}
-
-double f0 (double x)
-{
-	cl++;
-	(void)x;
-
-	return 1;
-}
-
-double f1 (double x)
-{
-	cl++;
-	return x + 1;
-}
-
-double f2 (double x)
-{
-	cl++;
-	return x * x + x + 1;
-}
-
-double f3 (double x)
-{
-	double x_2 = x * x;
-	cl++;
-
-	return x * x_2 + x_2 + x + 1;
-}
-
-double f4 (double x)
-{
-	double x_2 = x * x;
-	double x_3 = x_2 * x;
-	cl++;
-
-	return x * x_3 + x_3 + x_2 + x + 1;
-}
-
-double f5 (double x)
-{
-	cl++;
-	return exp(-x);
-}
-
-double f6 (double x)
-{
-	cl++;
-	return 1 / (25 * x * x + 1);
-}
-

2025.05.09/04Ex/init_f.h

@@ -1,13 +1,66 @@
 #ifndef INIT_F_H
 #define INIT_F_H
 
-int get_call_count (void); 
+#include <math.h>
-double f0 (double x);
+
-double f1 (double x);
+static int cl = 0;
-double f2 (double x);
+
-double f3 (double x);
+static inline int get_call_count (void) 
-double f4 (double x);
+{
-double f5 (double x);
+	return cl;
-double f6 (double x);
+}
+
+static inline double f0 (double x)
+{
+	cl++;
+	(void)x;
+
+	return 1;
+}
+
+static inline double f1 (double x)
+{
+	cl++;
+	return x + 1;
+}
+
+static inline double f2 (double x)
+{
+	double x_2 = x * x;
+	cl++;
+	return x_2 + x + 1;
+}
+
+static inline double f3 (double x)
+{
+	double x_2 = x * x;
+	double x_3 = x_2 * x;
+	cl++;
+
+	return x_3 + x_2 + x + 1;
+}
+
+static inline double f4 (double x)
+{
+	double x_2 = x * x;
+	double x_3 = x_2 * x;
+	double x_4 = x_3 * x;
+	cl++;
+
+	return x_4 + x_3 + x_2 + x + 1;
+}
+
+static inline double f5 (double x)
+{
+	cl++;
+	return exp(-x);
+}
+
+static inline double f6 (double x)
+{
+	double x_2 = x * x;
+	cl++;
+	return 1 / (25 * x_2 + 1);
+}
 
 #endif

2025.05.09/04Ex/main.c

@@ -9,8 +9,8 @@
 /* ./a04.out a b n k */
 int main (int argc, char *argv[])
 {
-	double t, x, a, b;
+	double t, integral, a, b;
-	int k, n, cl, task = 4;
+	int k, n, calls, task = 4;
 	
 	double (*f_lst[]) (double) = {f0, f1, f2, f3, f4, f5, f6};
 	int len_f = sizeof(f_lst) / sizeof(f_lst[0]);
@@ -20,26 +20,24 @@ int main (int argc, char *argv[])
 			sscanf(argv[1], "%lf", &a) == 1 &&
 			sscanf(argv[2], "%lf", &b) == 1 &&
 			((sscanf(argv[3], "%d", &n) == 1) && (n > 0)) &&
-			((sscanf(argv[4], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
+			((sscanf(argv[4], "%d", &k) == 1) && ((0 <= k) && (k < len_f))))
 	) {
-		fprintf(stderr, "Usage: %s x h k\n", argv[0]);
+		fprintf(stderr, "Usage: %s a b n k\n", argv[0]);
 		return -1;
 	}
 
 
 	t = clock();
-	d = t4_solve(f_lst[k], x, h);
+	integral = t4_solve(f_lst[k], a, b, n);
 	t = (clock() - t) / CLOCKS_PER_SEC;
 	
-	cl = get_call_count();
+	calls = get_call_count();
 
-	if (fabs(d - DBL_MAX) < DBL_EPSILON)
+	if (fabs(integral - DBL_MAX) < DBL_EPSILON) {
-	{
+		fprintf (stdout, "%s : Task = %d Method is not applicable Count = %d T = %.2f\n", argv[0], task, calls, t);
-		fprintf (stdout, "%s : Task = %d Method is not applicable Count = %d T = %.2f\n", argv[0], task, cl, t);
 		return -2;
-	} else
+	} else {
-	{
+		fprintf (stdout, "%s : Task = %d Res = %e Count = %d T = %.2f\n", argv[0], task, integral, calls, t);
-		fprintf (stdout, "%s : Task = %d Res = %e Count = %d T = %.2f\n", argv[0], task, d, cl, t);
 		return 0;
 	}
 }

2025.05.09/04Ex/solve.c

@@ -3,12 +3,24 @@
 #include <math.h>
 #include <float.h>
 
-int t3_solve (
+double t4_solve (
 		double (*f) (double), 
-		double x, double h 
+		double a, double b,
+		int n	
 ) {
-	if (h < DBL_EPSILON)
+	const double h = (b - a) / n;
+	double x = a;
+	double sum = (f(a) + f(b)) * 0.5;
+
+	if (h < NUM_FPE)
 		return DBL_MAX;
-	return (f(x + h) - 2 * f(x) + f(x - h)) / (h * h);
+	
+	for (int i = 1; i < (n - 1); ++i)
+	{
+		x += h;
+		sum += f(x);
+	}
+
+	return h * sum;
 }
 

2025.05.09/04Ex/solve.h

@@ -1,9 +1,12 @@
 #ifndef SOLVE_H
 #define SOLVE_H
 
-int t3_solve (
+#define NUM_FPE 1e-300
+
+double t4_solve (
 		double (*f) (double), 
-		double x, double h 
+		double a, double b,
+		int n	
 );
 
 #endif

2025.05.09/05Ex/Makefile

@@ -0,0 +1,42 @@
+WFLAGS = -fstack-protector-all -W -Wall -Wextra -Wunused \
+-Wempty-body -Wlogical-op -Wold-style-declaration -Wmissing-parameter-type \
+-Wignored-qualifiers -Winit-self -Wshadow -Wtype-limits \
+-Wpointer-arith -Wformat-security -Wmissing-format-attribute -Wformat=1 \
+-Wdeclaration-after-statement -Wbad-function-cast -Wnested-externs \
+-Wmissing-prototypes -Wmissing-declarations -Wold-style-definition \
+-Wcast-align -Werror -pedantic -pedantic-errors -Wfloat-equal \
+-Wwrite-strings -Wno-long-long -std=gnu99 -Wstrict-prototypes \
+-Wmissing-field-initializers -Wpointer-sign
+
+LDFLAGS = -std=gnu99 -mfpmath=sse -O3
+LDLIBS = -lm
+
+ifeq ($(OS),Windows_NT)
+	EXE = exe
+	CLEAN = del
+	LDLIBS += -lssp
+else
+	EXE = out
+	CLEAN = rm -f
+endif
+
+TARGET = a05.$(EXE)
+OBJ = main.o solve.o 
+
+%.o: %.c
+	gcc $(WFLAGS) $(LDFLAGS) -c $< -o $@
+
+$(TARGET): $(OBJ)
+	gcc $^ -o $@ $(LDLIBS)
+
+# Отладочная сборка (gdb)
+gdb: LDFLAGS = -std=gnu99 -mfpmath=sse -g -O0
+gdb: clean $(TARGET)
+
+# Профилировочная сборка (gprof)
+prof: LDFLAGS += -pg
+prof: LDLIBS += -pg
+prof: clean $(TARGET)
+
+clean:
+	$(CLEAN) *.o *.$(EXE)

2025.05.09/05Ex/init_f.h

@@ -0,0 +1,66 @@
+#ifndef INIT_F_H
+#define INIT_F_H
+
+#include <math.h>
+
+static int cl = 0;
+
+static inline int get_call_count (void) 
+{
+	return cl;
+}
+
+static inline double f0 (double x)
+{
+	cl++;
+	(void)x;
+
+	return 1;
+}
+
+static inline double f1 (double x)
+{
+	cl++;
+	return x + 1;
+}
+
+static inline double f2 (double x)
+{
+	double x_2 = x * x;
+	cl++;
+	return x_2 + x + 1;
+}
+
+static inline double f3 (double x)
+{
+	double x_2 = x * x;
+	double x_3 = x_2 * x;
+	cl++;
+
+	return x_3 + x_2 + x + 1;
+}
+
+static inline double f4 (double x)
+{
+	double x_2 = x * x;
+	double x_3 = x_2 * x;
+	double x_4 = x_3 * x;
+	cl++;
+
+	return x_4 + x_3 + x_2 + x + 1;
+}
+
+static inline double f5 (double x)
+{
+	cl++;
+	return exp(-x);
+}
+
+static inline double f6 (double x)
+{
+	double x_2 = x * x;
+	cl++;
+	return 1 / (25 * x_2 + 1);
+}
+
+#endif

2025.05.09/05Ex/main.c

@@ -0,0 +1,44 @@
+#include <stdio.h>
+#include <time.h>
+#include <math.h>
+#include <float.h>
+
+#include "init_f.h"
+#include "solve.h"
+
+/* ./a04.out a b n k */
+int main (int argc, char *argv[])
+{
+	double t, integral, a, b;
+	int k, n, calls, task = 5;
+	
+	double (*f_lst[]) (double) = {f0, f1, f2, f3, f4, f5, f6};
+	int len_f = sizeof(f_lst) / sizeof(f_lst[0]);
+
+	if (
+			!((argc == 5) && 
+			sscanf(argv[1], "%lf", &a) == 1 &&
+			sscanf(argv[2], "%lf", &b) == 1 &&
+			((sscanf(argv[3], "%d", &n) == 1) && (n > 0)) &&
+			((sscanf(argv[4], "%d", &k) == 1) && ((0 <= k) && (k < len_f))))
+	) {
+		fprintf(stderr, "Usage: %s a b n k\n", argv[0]);
+		return -1;
+	}
+
+
+	t = clock();
+	integral = t5_solve(f_lst[k], a, b, n);
+	t = (clock() - t) / CLOCKS_PER_SEC;
+	
+	calls = get_call_count();
+
+	if (fabs(integral - DBL_MAX) < DBL_EPSILON) {
+		fprintf (stdout, "%s : Task = %d Method is not applicable Count = %d T = %.2f\n", argv[0], task, calls, t);
+		return -2;
+	} else {
+		fprintf (stdout, "%s : Task = %d Res = %e Count = %d T = %.2f\n", argv[0], task, integral, calls, t);
+		return 0;
+	}
+}
+

2025.05.09/05Ex/solve.c

@@ -0,0 +1,26 @@
+#include "solve.h"
+
+#include <math.h>
+#include <float.h>
+
+double t5_solve (
+		double (*f) (double), 
+		double a, double b,
+		int n	
+) {
+	const double h = (b - a) / (2 * n);
+	double x = a;
+	double sum = (f(a) + f(b)) * 0.5;
+
+	if (h < NUM_FPE)
+		return DBL_MAX;
+	
+	for (int i = 1; i < (2 * n - 1); ++i)
+	{
+		x += h;
+		sum += ((i & 1) + 1) * f(x);
+	}
+
+	return (b - a) * sum / (3 * n);
+}
+

2025.05.09/05Ex/solve.h

@@ -0,0 +1,12 @@
+#ifndef SOLVE_H
+#define SOLVE_H
+
+#define NUM_FPE 1e-300
+
+double t5_solve (
+		double (*f) (double), 
+		double a, double b,
+		int n	
+);
+
+#endif