2nd_Sem_Bogachev/2025.05.02/dist/Ryabov_AD/task06.c
2025-05-02 02:22:11 +03:00

74 lines
No EOL
1.8 KiB
C

#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include "solve.h"
#include "make_f.h"
int main(int argc, char*argv[]){
double *d;
int m, k, deg;
double t, res;
int ret;
double a, b, eps;
double (*f)(double);
if (!(argc == 7 && sscanf(argv[1], "%d", &deg) == 1 && sscanf(argv[2], "%lf", &a) == 1 && sscanf(argv[3], "%lf", &b) == 1 && sscanf(argv[4], "%lf", &eps) == 1 && sscanf(argv[5], "%d", &m) == 1 && sscanf(argv[6], "%d", &k) == 1)){
printf("Usage %s\n", argv[0]);
return 1;
}
if (b <= a){
printf("[a;b] not segment\n");
return 4;
}
if (!(0 <= k && k <= 6)){
printf("k - number of formula doesn't match options\n");
return 2;
}
if (m <= 0){
printf("Number of iterations must be positive number\n");
return 3;
}
if (deg <= 0){
printf("deg < 0 is no\n");
return 5;
}
switch (k){
case (0):
f = f0;
break;
case (1):
f = f1;
break;
case (2):
f = f2;
break;
case (3):
f = f3;
break;
case (4):
f = f4;
break;
case (5):
f = f5;
break;
case (6):
f = f6;
break;
}
// создаём массив d
d = (double *)malloc(3 * (deg + 1) * sizeof(double));
if (!d){
printf("No pamyat\n");
return 2;
}
t = clock();
ret = task06(f, deg, d, a, b, eps, m, &res);
t = (clock() - t) / CLOCKS_PER_SEC;
if (ret >= 0){
printf ("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], 6, res, f(res), ret, c(), t);
}
else{
printf("%s : Task = %d NOT FOUND Count = %d T = %.2f\n", argv[0], 6, c(), t);
}
free(d);
return 0;
}