2nd_Sem_Bogachev/2025.05.02/dist/Ulyanov_MT/task09.c
2025-05-02 01:18:28 +03:00

65 lines
1.7 KiB
C

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <time.h>
#include "io_status.h"
#include "functions.h"
#include "comparison.h"
int solve9(double, double, double, int, double*, double (*)(double));
int main(int argc, char* argv[])
{
int task = 9;
double a, b, eps;
int maxit, k;
double t;
double (*f)(double);
double (*func[])(double) = {f0, f1, f2, f3, f4, f5, f6};
double x = 0, fx;
int it, c;
if (!(argc == 6 && sscanf(argv[1], "%lf", &a) == 1 && sscanf(argv[2], "%lf", &b) == 1 && sscanf(argv[3], "%le", &eps) == 1 && sscanf(argv[4], "%d", &maxit) == 1 && sscanf(argv[5], "%d", &k) == 1 && k >= 0 && k <= 6))
{
printf("Usage: %s a b eps M k\n", argv[0]);
return -2;
}
f = func[k];
t = clock();
it = solve9(a, b, eps, maxit, &x, f);
t = (clock() - t) / CLOCKS_PER_SEC;
c = get_count();
if (it < 0)
{
printf("%s : Task = %d NOT FOUND Count = %d T = %.2f\n", argv[0], task, c, t);
return -1;
}
fx = (*f)(x);
printf("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], task, x, fx, it, c, t);
return 0;
}
int solve9(double a, double b, double eps, int maxit, double* x, double (*f)(double))
{
int it;
double phi = 2 / (1 + sqrt(5));
double x1 = b - (b - a) * phi, x2 = a + (b - a) * phi;
double fx1 = (*f)(x1), fx2 = (*f)(x2);
for (it = 0; it < maxit; it++)
{
if (fx1 < fx2)
{
a = x1;
x1 = x2; fx1 = fx2;
x2 = a + (b - a) * phi; fx2 = (*f)(x2);
}
else
{
b = x2;
x2 = x1; fx2 = fx1;
x1 = b - (b - a) * phi; fx1 = (*f)(x1);
}
if (fabs(a - b) < eps) {*x = x1; break;}
}
if (it >= maxit) return -1;
return it;
}