2nd_Sem_Bogachev/2025.03.21/10Ex/solve.c
2025-03-19 17:44:00 +03:00

71 lines
1.3 KiB
C

#include "solve.h"
#include <math.h>
#include <float.h>
#include <stdio.h>
int t10_solve(double *a, int m, int n)
{
int min_i = 0, min_j = 0;
double minimum = DBL_MAX;
double inn = 1./n, inm = 1./m;
for (int i = 0; i < m; i++)
{
double cur = 0;
double sum = 0;
double sq_sum = 0;
for (int j = 0; j < n; j++)
{
double temp = a[i*n + j];
sum += temp;
sq_sum += temp * temp;
}
cur = sq_sum - (sum * sum) * inn;
if ((minimum - cur) > DBL_EPSILON * fmax(fabs(minimum), fabs(cur))) {
minimum = cur;
min_i = i;
}
}
minimum = DBL_MAX;
for (int j = 0; j < n; j++)
{
const int BS = 32;
double cur = 0;
double sum = 0;
double sq_sum = 0;
for (int ii = 0; ii < m; ii += BS)
for (int i = ii; i < ii + BS && i < m; i++)
{
double temp = a[i*n + j];
sum += temp;
sq_sum += temp * temp;
}
cur = sq_sum - (sum * sum) * inm;
if ((minimum - cur) > DBL_EPSILON * fmax(fabs(minimum), fabs(cur))) {
minimum = cur;
min_j = j;
}
}
for (int l = min_j+1, del_j = 1; l < min_i*n; l++)
{
if (l == ((n * del_j) + min_j))
del_j++;
else
a[l - del_j] = a[l];
}
for (int l = (min_i+1)*n, del_j = min_i; l < m*n; l++)
{
if (l == ((n * (del_j + 1)) + min_j))
del_j++;
else
a[l - del_j - n] = a[l];
}
return min_i * n + min_j;
}