49 lines
1.1 KiB
C
49 lines
1.1 KiB
C
#include <stdio.h>
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#include <time.h>
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#include <math.h>
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#include "init_f.h"
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#include "solve.h"
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/* ./a.out a b eps M k */
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int main(int argc, char *argv[])
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{
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double t, a, b, eps, x = 0;
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int m, k, cl, it, task = 10;
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double (*f) (double);
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double (*f_lst[]) (double) = {f0, f1, f2, f3, f4, f5, f6};
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int len_f = sizeof(f_lst) / sizeof(f_lst[0]);
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if (
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!((argc == 6) &&
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sscanf(argv[1], "%lf", &a) == 1 &&
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sscanf(argv[2], "%lf", &b) == 1 &&
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(a <= b) &&
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(sscanf(argv[3], "%lf", &eps) == 1 && (eps >= 0)) &&
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((sscanf(argv[4], "%d", &m) == 1) && m > 0) &&
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((sscanf(argv[5], "%d", &k) == 1) && ((0 <= k) && (k <= len_f))))
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) {
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fprintf(stderr, "Usage: %s a b eps M k\n", argv[0]);
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return -1;
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}
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f = f_lst[k];
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t = clock();
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it = t10_solve(f, a, b, eps, m, &x);
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t = (clock() - t) / CLOCKS_PER_SEC;
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cl = get_call_count();
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if (it < 0)
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{
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fprintf(stdout, "%s : Task = %d NOT FOUND Count = %d T = %.2f\n", argv[0], task, cl, t);
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return -2;
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} else
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{
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printf("%s : Task = %d X = %e Res = %e Its = %d Count = %d T = %.2f\n", argv[0], task, x, f(x), it, cl, t);
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return 0;
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}
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}
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